H2O pH is always...7, could be acid (pH) or base (pOH)
Frozen!
Frozen!
how to increase/decrease buffering capacity
strong acid strong base equivalence pointpH = 7 @ 25 C / 298 K
what is a buffersolution that is resistant to a small pH change, it has to contain a weak acid or base pared with its conjugate salt(Na+, H3O-, etc...) and it creates neutral compounds, keeping pH relatively stable
in what range are buffers effectivewithin 1 pH of its pKa, up or down
pH + pOH =14 always!!
Frozen!
Frozen!
how do you calculate a buffer's pH
strong acid-weak base reaction
maximum buffering capacitypH = pKa
weak acid-strong base reactionHA(aq) + OH- --> A-(aq) + H2O(L)
if weak acid is in excess --> a buffer --> Hendeson Hasselbalch equaiton
if strong base is in excess, the moles of excess hydroxide ions is used for pH
if acid and base are equimolar then the equilibrium concentr
equivalence pointstraight line up part of graph
#miles of titrant = #moles of analyte
concentration and volume of titrant is then used to determine concentration of analyte
Boost!
Boost!
1.0 x 10^-14 at 25 C or 298 K
what is a buffersolution that is resistant to a small pH change, it has to contain a weak acid or base pared with its conjugate salt(Na+, H3O-, etc...) and it creates neutral compounds, keeping pH relatively stable
Frozen!
Frozen!
in what range are buffers effectivewithin 1 pH of its pKa, up or down
maximum buffering capacitypH = pKa
how to increase/decrease buffering capacity
7, could be acid (pH) or base (pOH)
strong acid strong base equivalence pointpH = 7 @ 25 C / 298 K
equivalence point
pH = pKa + log [A-]/[HA] ---> acids
pOH = pKb + log [BH+]/[B] ---> bases
the conjugate salt is on top, and the bottom is either the base or the acid
assume there is a limiting and excess reagent (because it will contain either a strong acid or base)
HA(aq) + OH- --> A-(aq) + H2O(L)
if weak acid is in excess --> a buffer --> Hendeson Hasselbalch equaiton
if strong base is in excess, the moles of excess hydroxide ions is used for pH
if acid and base are equimolar then the equilibrium concentr
14 always!!
strong acid-weak base reactionif weak base is in excess --> a buffer --> Hendeson Hasselbalch equaiton
if strong acid is in excess, the moles of excess acid are used to determine pH
if acid and base are equimolar then the equilibrium concentrations are used to determine pH